Answer:
The correct answer is "-1.5 cm".
Explanation:
The given values are:
Object is placed,
u = 2.5 cm
Focal length,
f = 1.5 cm
On applying the lens formula, we get
⇒ [tex]\frac{1}{u} +\frac{1}{v} =\frac{1}{f}[/tex]
or,
⇒ [tex]\frac{1}{v} =\frac{1}{u} -\frac{1}{f}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{1}{2.5} -\frac{1}{1.5}[/tex]
⇒ [tex]=\frac{1.5-2.5}{3.75}[/tex]
⇒ [tex]=\frac{-1}{3.75}[/tex]
⇒ [tex]v=-3.75 \ cm[/tex]
As we know,
Magnification, [tex]m=\frac{v}{u}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{-3.75}{2.5}[/tex]
⇒ [tex]=-1.5 \ cm[/tex]
