Answer:
t = 4.19 s, θ = 0.437 rad
Explanation:
This is an exercise in rotational kinematics in this case we indicate the angular velocity and the angular acceleration, asking for the time and the angle it takes to stop.
w = w₀ + α t
w² = w₀² + 2 α θ
when the system stops the angular velocity is zero
0 = w₀- α t
0 = w₀² - 2 α θ
t = w₀ / α
tea = w₀² / 2 α
let's reduce the magnitudes to the SI system
w₀ = 2 rpm (2π rad / 1 rev) (1 min / 60s) = 0.209 rad / s
let's calculate
t = 0.209 / 0.05
t = 4.19 s
θ = 0.209 2/2 0.05
θ = 0.437 rad
