Answer:
[tex]L_c=25.12ft[/tex]
Step-by-step explanation:
From the question we are told that
Width of circular path [tex]w_c=4ft[/tex]
Inner Diameter [tex]d_i_n=550ft[/tex]
Outer diameter [tex]d_{out}= 550 +2*4[/tex] (inner diameter + 2 circular path width)
[tex]d_{out}= 550 +8\\d_{out}= 558ft[/tex]
Generally the equation for inner circumference of the circle [tex]C_1[/tex] is mathematically given by
[tex]C_1=\pi d_{in}[/tex]
[tex]C_1=3.14*550[/tex]
[tex]C_1=1727ft[/tex]
Generally the equation for outer circumference of the circle [tex]C_2[/tex] is mathematically given by
[tex]C_2=\pi d_{out}[/tex]
[tex]C_2=3.14*558[/tex]
[tex]C_2=1752.12ft[/tex]
Generally the difference in length of the two circumference [tex]L_c[/tex] is mathematically given by
[tex]L_c=C_2-C_1[/tex]
[tex]L_c=1752.12-1727[/tex]
[tex]L_c=25.12ft[/tex]
