The half-life of carbon-14 is 5,730 years. Suppose a fossil is found with 20 percent as much of its carbon-14 as compared to a living sample. How old is the fossil

Respuesta :

Answer: The sample is 13414 years old.

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant= 100

a - x = amount left after decay process= [tex]\frac{20}{100}\times 100=20[/tex]

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]

[tex]k=\frac{0.693}{5730}=0.00012years^{-1}[/tex]

b) for completion of 20% of reaction

[tex]t=\frac{2.303}{0.00012}\log\frac{100}{20}[/tex]

[tex]t=13414years[/tex]

The sample is 13414 years old.