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The wheelchair starts from rest. It accelerates at a constant rate until it has a speed of 1.5 m/s. The wheelchair travels a distance of 2.0 m while it is accelerating. Calculate the acceleration of the wheelchair.


Please help me i have a test and i have zero idea how to do thiss............

Respuesta :

GodSlayer007

Answer:-

[tex]\pink{\bigstar}[/tex] The acceleration of the wheelchair is [tex]\large\leadsto\boxed{\tt\purple{0.5625 \: m/s^2}}[/tex]

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• Given:-

  • Initial velocity of the wheelchair = 0 m/s

  • Final velocity of the wheelchair = 1.5 m/s

  • Distance covered by the wheelchair = 2 m

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• To Find:-

  • Acceleration of the wheelchair = ?

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• Solution:-

We know,

• Third Equation of Motion:-

[tex]\pink{\bigstar}[/tex] [tex]\large\underline{\boxed{\bf\green{v^2 - u^2 = 2as}}}[/tex]

where,

  • u = Initial velocity

  • v = Final velocity

  • a = Acceleration

  • s = Distance covered

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• Substituting the values in the Formula:-

➪ [tex]\sf (1.5)^2 - (0)^2 = 2 \times a \times 2[/tex]

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➪ [tex]\sf 2.25 - 0 = 4 \times a[/tex]

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➪ [tex]\sf 2.25 = 4 \times a[/tex]

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➪ [tex]\sf a = \dfrac{2.25}{4}[/tex]

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★ [tex]\large{\bold\red{a = 0.5625 \: m/s^2}}[/tex]

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Therefore, the acceleration of the wheelchair is 0.5625 m/s².

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