Respuesta :

Answer:

97.9

Explanation:

m= n*M

M CaCl2= 40+ 35.5*2= 110

m= 0.89*110= 97.9

The mass of the given mole of [tex]CaCl_2[/tex] is required.

The mass of the given compound is 98.78 g.

Molar mass of [tex]CaCl_2[/tex]

[tex]M=40.078+35.453\times 2=110.984\ \text{g/mol}[/tex]

n = Number of moles = 0.89 mol

Mass is given by

[tex]m=Mn\\\Rightarrow m=110.984\times 0.89\\\Rightarrow m=98.78\ \text{g}[/tex]

The mass of the given compound is 98.78 g.

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