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stoichiometry is hawd

Using the following reaction:

C12H22O11 + 12 O2 → 12CO2 + 11H2O + energy

How many grams of carbon dioxide, CO2, are produced from metabolizing 448g sucrose?

Respuesta :

Space

Answer:

691 g CO₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Moles

Organic

  • Organic Compounds CₓHₙ

Stoichiometry

  • Using Dimensional Analysis
  • Analyzing Reactions RxN

Explanation:

Step 1: Define

[RxN - Balanced] C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O + Energy

[Given] 448 g C₁₂H₂₂O₁₁ (sucrose)

[Solve] grams CO₂ (carbon dioxide)

Step 2: Identify Conversions

[RxN] 1 mol C₁₂H₂₂O₁₁ → 12 mol CO₂

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of C₁₂H₂₂O₁₁ - 12(12.01) + 22(1.01) + 11(16.00) = 342.34 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Stoich

  1. [DA] Set up conversion:                                                                                   [tex]\displaystyle 448 \ g \ C_{12}H_{22}O_{11}(\frac{1 \ mol \ C_{12}H_{22}O_{11}}{342.34 \ g \ C_{12}H_{22}O_{11}})(\frac{12 \ mol \ CO_2}{1 \ mol \ C_{12}H_{22}O_{11}})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})[/tex]
  2. [DA] Multiply/Divide [Cancel out units]:                                                           [tex]\displaystyle 691.119 \ g \ CO_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

691.119 g CO₂ ≈ 691 g CO₂