Respuesta :

tonb

Answer:

I = 11/2 = 5.5

R = 60/11 ≈ 5.5Ω

Explanation:

You use V = I·R twice.

Entire circuit: 140 = I·(20+R)

Resistor: 30 = I·R

Solving this system of equations gives:

140 = I·(20+R) = 20I + IR

30 = I·R

140 = 20I + 30

20I = 110

I = 11/2 = 5.5

R = 60/11 ≈ 5.5Ω