Answer:
327.58 kPa
Explanation:
Given data; 1st wave
Amplitude ( A1 ) = 293 Kpa
frequency = 6Hz
Average stress = 2388kPa
phase angle = 90° ( leading )
Determine the amplitude of the second sinusoidal component in kPa
Amplitude of additional wave ( A2 ) = 293 / 2 = 146.5 kPa
Amplitude of first wave ( A 1 ) = 293 kPa
hence the amplitude of the second sinusoidal component
A' = [tex]\sqrt{} A^{2} _{1} } + A^2_{2} + 2A_{1} A_{2} *cos 90[/tex]
= [tex]\sqrt293^2 + 146.5^2 + 2(293*146.5) *( -0.45)[/tex]
= [tex]\sqrt{85849+ 21462.25}[/tex]
= 327.58 kPa