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An optical inspection system is used to distinguish among different part types. The probability of a correct classification of any part is 0.93. Suppose that three parts are inspected and that the classifications are independent. Let the random variable X denote the number of parts that are correctly classified. Determine the probability mass function of X.
Probability Mass Function of X
x f(x)
0
1
2
3

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Answer:

Follows are the solution to this question:

Step-by-step explanation:

Let P(X = x) mark x model number classified correctly.

The mass function of the probability:

[tex]\to f(0) = P(X=0) = (0.03)^3 = 0.0000\\\\\to f(1) = P(X=1) = (3 C_1)\times (0.97)\times (0.03)^2 = 0.0026\\\\\to f(2) = P(X=2) = (3 C_2)\times (0.97)^2 \times (0.03) = 0.0847\\\\\to f(3) = P(X=3) = (0.97)^3 = 0.9127\\\\[/tex]

[tex]x \ \ \ \ f(x) \\\\0\ \ \ \ 0.0000\\\\1\ \ \ \ 0.0026\\\\2\ \ \ \ 0.0847\\\\3\ \ \ \ 0.9127[/tex]

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