Answer:
the diver's speed just before she enters the water is 8.718 m/s.
Explanation:
Given;
height of the diving platform, h = 3.8 m
initial velocity of the diver, u = 1.24 m/s
the diver's speed just before she enters the water is her final velocity, = v
Apply the following kinematic equation to determine the final velocity of the girl;
v² = u² + 2gh
v² = (1.24)² + 2(9.8 x 3.8)
v² = 76.018
v = √76.018
v = 8.718 m/s
Therefore, the diver's speed just before she enters the water is 8.718 m/s.
