Respuesta :
Answer:
Imelda has 5 more pairs of shoes than Sonia and Danielle have combined.
Step-by-step explanation:
This question can be solved by a system of equations.
I am going to say that:
Sonia has x pairs of shoes.
Danielle has y pairs of shoes.
Imelda has z pairs of shoes.
Sonia has five more pairs of shoes than Danielle.
This means that
[tex]x = y + 5[/tex]
Imelda has twice as many pairs of shoes as Sonia.
This means that [tex]z = 2x[/tex]
Altogether, the girls have 39 pairs of shoes.
This means that [tex]x + y + z = 39[/tex]
Since [tex]x = y + 5, z = 2x = 2(y + 5)[/tex]
[tex]x + y + z = 39[/tex]
[tex]y + 5 + y + 2y + 10 = 39[/tex]
[tex]4y + 15 = 39[/tex]
[tex]4y = 24[/tex]
[tex]y = \frac{24}{4}[/tex]
[tex]y = 6[/tex]
Danielle has 6 pairs.
Sonia:
[tex]x = y + 5 = 6 + 5 = 11[/tex]
Sonia has 11 pairs.
Imelda:
[tex]z = 2x = 2(11) = 22[/tex]
Imelda has 22 pairs.
How many more pairs of shoes does Imelda have than Sonia and Danielle have combined?
Imelda has 22 pairs.
Sonia and Danielle combined have 11 + 6 = 17 pairs.
22 - 17 = 5
Imelda has 5 more pairs of shoes than Sonia and Danielle have combined.
