Respuesta :
Answer:
a) g’= 3.44 10⁻⁵ m / s²
b) g ‘’ = 5.934 10⁻³ m / s²
Explanation:
For this exercise let's use the law of universal gravitation
F = [tex]G \frac{m M}{r^2}[/tex]
where m is the mass of the body under study, M the mass of the body that creates the force and r the distance between the bodies
F = [tex]m \ ( G \frac{M}{r^2} )[/tex]
the attractive force is called weight W = m g,
Thus
g = [tex]G \frac{M}{r^2}[/tex]
is called the acceleration of gravity
a) the acceleration created by the moon
g' = G \frac{M}{r^2}
the mass of the moon is M = 7.36 10²² kg
the distance from the moon to the Earth's surface is
r = D -R_e
r = 3.84 10⁸ -6.37 10⁶
r = 3.7763 10⁸ m
we calculate
g’= [tex]6.67 \ 10^{-11} \ \frac{7.36 \ 10^{22}}{ (3.7763 \ 10^8)^2}[/tex]
g ’= 3.44 10⁻⁵ m / s²
b) the acceleration created by the sun
mass of the sun M = 1,9991 10³⁰ ka
the distance from the sun wears down the Earth's surface
r = D -R_e
r = 1.496 10¹¹ -6.37 10⁶
r = 1.4959 10¹¹ m
let's calculate
g ’’ = [tex]6.67 \ 10^{-11} \frac{1.991 \ 10^{30}}{ (1.4959 \ 10^{11})^2 }[/tex]
g ‘’ = 5.934 10⁻³ m / s²
