Hannah and Omar Only used a formula that will help them prove the relationship.
Proportionally
A line drawn parallel to one side of a Δ divides the other two sides in the same ratio.
Given
To prove that DE divides AB and AC proportionally.
Construction: If DE is not parallel to BC, draw DF meeting AC at F.
Proof: In ΔABC, let DF || BC
[tex]\rm \dfrac{AD}{DB}=\dfrac{AC}{FC}\\\\[/tex]
A line drawn parallel to one side of a Δ divides the other two sides in the same ratio.
[tex]\rm \dfrac{AD}{DB}=\dfrac{AE}{EC}\\\\[/tex]
From (i) and (ii), we get
[tex]\rm \dfrac{AD}{DB}=\dfrac{AC}{FC}=\rm \dfrac{AE}{EC}\\\\[/tex]
Hence, Hannah and Omar Only used a formula that will help them prove the relationship.
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