Answer:flow velocity of the water leaving the end of the hose is 31.87 cm/s or 0.3187 m/s
Explanation:
Given that
Diameter of hose, d = 5/8 in
changing to cm becomes
1 inch =2.54 cm
5/ 8 inch=0.625 x 2.54= 1.5875cm
Volume of water filled = 2gallons
changing to cubic centimeters
1 gallon = 3785.41cm^3
2 gallons = 3785.41 x 2 =7570.82cm^3
Time, t = 2 min
60 sec= 1 min
?? sec = 2 min
= 120 secs
The volumetric flow rate of water, F is given as
F = V/t = 7570.82cm^3÷ 120 seconds
F = 63.09 cm^3/s
We Know that The volumetric flow rate is also equal the cross sectional area of pipe times the speed of flow(velocity of flow). ie
F = Av
v = F/A
Since Area A = πd^2/4
v = F/(πd^2/4)
v = 4F/πd^2
Puting the given values;
v = (4× 63.09 )/(π×1.5875²)
v = 252.36/πx 2.5202
v = 31.869 cm/s =31.87cm/s 0r 0.3187m/s
Therefore flow velocity of the water leaving the end of the hose is 31.87 cm/s or 0.3187 m/s
