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For every 3.3 km a rock is buried, the pressure placed upon it increases 0.1 gigapascal (100 million pascals). If rock undergoing metamorphosis is buried at 16 km, what is the pressure placed on that rock? (Hint: The pressure of Earth's surface is .101 gigapascal.)

Respuesta :

MrRoyal

Answer:

[tex]x = 0.48485\ GPa[/tex]

Explanation:

Given

[tex]Rate = 0.1GPa/3.3km[/tex]

Required:

Determine its pressure at 16km

Let the pressure at 16km be x.

So, the rate at 16km is:

[tex]Rate = x/16km[/tex]

Equate both rates

[tex]x/16km = 0.1GPa/3.3km[/tex]

Multiply both sides by 16

[tex]16km * x/16km = 0.1GPa/3.3km * 16km[/tex]

[tex]x = 0.1GPa/3.3 * 16[/tex]

[tex]x = 1.6GPa/3.3[/tex]

[tex]x = 0.48485\ GPa[/tex]

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