Respuesta :
Answer:
0.1490 = 14.90% probability that a randomly selected potential customer will purchase the product.
Step-by-step explanation:
Probability of seeing the ad:
I am going to find this probability using Venn Sets.
I am going to say that:
Event A: Sees a magazine ad.
Event B: Sees a television ad.
Approximately 1 in 50 potential buyers of a product sees a given magazine ad
This means that [tex]P(A) = \frac{1}{50} = 0.02[/tex]
1 in 5 sees a corresponding ad on television.
This means that [tex]P(B) = \frac{1}{5} = 0.2[/tex]
One in 100 see both.
This means that [tex]P(A \cap B) = \frac{1}{100} = 0.01[/tex]
The probability of seeing the ad is the probability of seeing at least one of those(magazine or tv), which is:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]. So
[tex]P(A \cup B) = 0.2 + 0.02 - 0.01[/tex]
[tex]P(A \cup B) = 0.21[/tex]
Probability of purchasing the product.
0.21 = 21% of customers see the add. Of those, 1/3 = 0.3333 buy the product.
1 - 0.21 = 0.79 = 79% of customers dont see the add. Of those, 1/10 = 0.1 buy the product. So
[tex]p= 0.21*0.3333 + 0.79*0.1 = 0.1490[/tex]
0.1490 = 14.90% probability that a randomly selected potential customer will purchase the product.
