Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the attachment of the given graph:
[tex]\to f(x)=\frac{2x^2+2x-84}{x^2-3x-18}[/tex]
[tex]=\frac{2(x^2+x-42)}{x^2-(6-3)x-18}\\\\=\frac{2(x^2+7x-6x-42)}{x^2-6x+3x-18}\\\\=\frac{2(x(x+7)-6(x+7))}{x(x-6)+3(x-6)}\\\\=\frac{2((x+7) (x-6))}{(x-6)(x+3)}\\\\=\frac{(2x+14)}{(x+3)}\\\\[/tex]
