Answer:
water temperature change = 0.696° F
Explanation:
In this question we will consider the steady flow energy equation at the Top and at the bottom of the water falls and also assume the flow is Adiabatic
we will apply the relation below to Estimate the water temperature change caused by the drop
[tex]C_{p} ( t ) = g ( z_{in} - z_{out} )[/tex] ------ ( 1 )
where : Cp = 25100 ft. Ibf / slug °F
Δ z = 543 ft
g = 32.2 ft/s^2
Input the given values into equation 1 and make t subject of the relation
t ( temp change ) = [tex]\frac{32.2 * 543}{25100}[/tex] = 0.696° F
