An orange rolls off a horizontal table with a speed of 0.5 ft./sec. It hits the ground half a second later. How high is the table? Remember that acceleration due to gravity is 32 ft./s^2
Answer Choices:
1 ft.
4 ft.
6 ft.
16 ft.
Please help urgently!

Respuesta :

The correct answer is:

4 ft.

The initial speed of the orange is zero in the downward direction and the height of the table is 4 ft then the correct option is B.

What is kinematics?

It is the study of the motion of a body without considering mass. And the reason behind them is neglected.

An orange rolls off a horizontal table with a speed of 0.5 ft./sec.

It hits the ground half a second later.

Then the height of the table will be

We know the formula

[tex]\rm s = ut + \dfrac{1}{2}at^2\\[/tex]

The final speed of the orange is zero because it hits the ground. Then we have

[tex]\rm -s = 0 \times 0.5+ \dfrac{1}{2}(-32)0.5^2\\\\-s = 0- 4\\\\s \ \ \ = 4[/tex]

The height of the table is 4 ft.

More about the kinematics link is given below.

https://brainly.com/question/25638908

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