Answer:
the Ā acceleration of the Ping Pong ball is Ā 200 m/sĀ²
Explanation:
Given;
mass of Ā Ping Pong ball, m = 0.0029 g = 2.9 x 10ā»ā¶ kg
mass of tennis ball, m = 0.058 g = 5.8 x 10ā»āµ kg
acceleration of the tennis ball, a = 10 m/sĀ²
The force applied to the tennis ball is calculated as;
F = ma
F = 5.8 x 10ā»āµ x 10
F = Ā 5.8 x 10ā»ā“ N
The acceleration of the Ping Pong ball is calculated as;
a = F/m
a = ( 5.8 x 10ā»ā“ N) / (2.9 x 10ā»ā¶)
a = 200 m/sĀ²
Therefore, the Ā acceleration of the Ping Pong ball is Ā 200 m/sĀ²
