Given:
Jacky leaves the office at 4:15 PM and she reaches her house at 4:55 PM.
Distance between office and her house = 25 km
To find:
The driving speed of Jacky.
Solution:
The difference between 4:15 PM and 4:55 PM is 40 minutes.
60 minute = 1 hour
1 minute = [tex]\dfrac{1}{60}[/tex] hour
40 minute = [tex]\dfrac{40}{60}[/tex] hour
= [tex]\dfrac{2}{3}[/tex] hour
We know that,
[tex]Speed=\dfrac{Distance}{Time}[/tex]
[tex]Speed=\dfrac{25}{\dfrac{2}{3}}[/tex]
[tex]Speed=\dfrac{3\times 25}{2}[/tex]
[tex]Speed=\dfrac{75}{2}[/tex]
[tex]Speed=37.5[/tex]
Therefore, the driving speed of Jacky is 37.5 km per hour.
