Answer:
154.44 Kg of Hâ‚‚
Explanation:
We'll begin by converting 139 Kg of water to grams. This can be obtained as follow:
1 kg = 1000 g
Therefore,
139 kg = 139 kg × 1000 g / 1 Kg
139 Kg = 139000 g
Next, the balanced equation. This is illustrated below:
2H₂ + O₂ —> 2H₂O
Next, we shall determine the mass of Hâ‚‚ that reacted and the mass of Hâ‚‚O produced from the balanced equation. This can be obtained as follow:
Molar mass of H₂ = 2 × 1 = 2 g/mol
Mass of H₂ from the balanced equation = 2 × 2 = 4 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16
= 18 g/mol
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY
From the balanced equation above,
4 g of Hâ‚‚ reacted to produce 36 g of Hâ‚‚O.
Next, we shall determine the mass of Hâ‚‚ needed to produce 139 kg (i.e 139000 g) of Hâ‚‚O. This can be obtained as follow:
From the balanced equation above,
4 g of Hâ‚‚ reacted to produce 36 g of Hâ‚‚O.
Therefore Xg of Hâ‚‚ will react to produce 139000 g of Hâ‚‚O i.e
Xg of H₂ = (4 × 139000)/36
Xg of Hâ‚‚ = 154444 g
Finally, we shall convert 154444 g to kg this can be obtained as follow:
1000 g = 1 Kg
Therefore,
154444 g = 154444 g × 1 Kg / 1000 g
154444 g = 154.44 Kg
Thus, 154.44 Kg of Hâ‚‚ is needed to produce 139 Kg of water Hâ‚‚O
