Respuesta :
The actual wavelength and observed wavelength of the sound is required.
The correct statement is
Wavelength of the stationary source: 11.25 ft; perceived wavelength: 10.25 ft
[tex]v[/tex] = Velocity of sound = 1125 ft/s
[tex]v_o[/tex] = Velocity of observer = 100 ft/s
[tex]f_s[/tex] = Frequency at source = 100 Hz
Actual wavelength
[tex]\lambda=\dfrac{v}{f_s}\\\Rightarrow \lambda=\dfrac{1125}{100}\\\Rightarrow \lambda=11.25\ \text{ft}[/tex]
Observed frequency
[tex]f_o=f_s(\dfrac{v+v_o}{v})\\ =100(\dfrac{1125+100}{1125})\\ =\dfrac{980}{9}\ \text{Hz}[/tex]
Observed wavelength
[tex]\lambda'=\dfrac{v}{f_o}\\ =\dfrac{1125}{\dfrac{980}{9}}\\ =10.33\ \text{ft}[/tex]
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