Answer:
ZnS is the limiting reactant.
Explanation:
Hello!
In this case, given the chemical reaction:
[tex]2ZnS+3O_2 \rightarrow 2ZnO+2SO_2[/tex]
Whereas there is a 2:2 and 3:2 mole ratios of the reactants to the SO2 product respectively. In such a way, we need to compute the moles of SO2 product that are yielded by each reaction as shown below:
[tex]n_{SO_2}^{by\ ZnS}=194gZnS*\frac{1molZnS}{97.47gZnS} *\frac{2molSO_2}{2molZnS} =1.99molSO_2\\\\n_{SO_2}^{by\ O_2}=256gO_2*\frac{1molO_2}{32.00gO_2} *\frac{2molSO_2}{3molO_2} =5.33molSO_2[/tex]
Thus, since zinc sulfide produces the fewest moles of SO2, we infer it is the limiting reactant.
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