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Tiles with the letters A, B, C, D, E, F, G, and H written on them are placed in a bag. Malik draws out one letter at random. Which statements about the situation are true? Check all that apply.

The number of possible outcomes is 8.

The probability of drawing the tile with E written on it is 1/4

P(vowel) = 1/4

P(vowel) + P(consonant) does not = 1

Choosing one letter at random is a simple event.​

Respuesta :

Phobic111

Answer:

P(vowel) = [tex]\frac{1}{4}[/tex]

Choosing one letter at random is a simple event.​

Step-by-step explanation:

P(vowel) =  [tex]\frac{1}{4}[/tex]

This is because there are 2 vowels so the probability [tex]\frac{2}{8}[/tex] is  which can be simplified to [tex]\frac{1}{4}[/tex] .

Moreover, Choosing one letter at random is a simple event.

The definition of a simple event is one that can only happen in one way, or in other words, it has a single outcome.

Malik's probability of drawing one letter at random is 1/4.

Probability calculation:

  • P (vowel) = [tex]\bold{ \frac{1}{4}}[/tex] It's good to select one letter at random. ​P(vowel)    = [tex]\bold{ \frac{1}{4}}[/tex]
  • Since there are two vowels, the probability is  [tex]\bold{ \frac{2}{8}}[/tex], is equal  [tex]\bold{ \frac{1}{4}}[/tex].
  • Furthermore, picking one letter at random is an easy procedure.
  • A simple event is one that can only happen one way or has just one conclusion.

Find out more about the probability here:

brainly.com/question/11234923

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