Answer :
[tex]\boxed{\textsf{ The final answer is \textbf{n}$^{\textbf{3}}$ .}}[/tex]
Step-by-step explanation:
Its given that n is the middle out of the three consecutive integers . So ,
The last integer will be :-
[tex]\sf\implies Last \ Integer \ = \ n - 1 [/tex]
The next Integer will be :-
[tex]\sf\implies Next \ Integer \ = \ n + 1 [/tex]
Now the Question says that the three integers are multipled to give a product . So that would be.
[tex]\sf\implies Product_{(three\ consecutive\ integers)}= (n-1)n(n+1) = (n^2-1)(n) = \pink{n^3-n}[/tex]
Now thirdly it's given that n is added to the given integer . That would be ,
[tex]\sf\implies Adding\ n = \ n^3 - n + n = \pink{n^3} [/tex]
Here - n and +n gets cancelled. So we are ultimately left out with nΒ³.
Hence the final number is a cube of some number.
