The perimeter of a rectangular painting with 42 centimeters wide and 52 centimeters long is 186 centimeters. This was obtained by using the perimeter of a rectangle formula [tex]2(l + b)[/tex].
Rectangle has 4 sides. one pair of sides are long and the other pair of sides are wide.
Then its perimeter is given by the sum of all its sides i.e.,
the perimeter of a rectangle = 2 × length of the long sides + 2 × width of the wide sides
∴ [tex]p = 2 ( l + b)[/tex]
Given that a rectangular painting has width w = 42 centimeters
and length l = 51 centimeters
On substituting,
perimeter = 2(51 + 42 )
= 2 × 93
= 186 centimeters
Therefore, the perimeter of the given rectangular painting with a width of 42 centimeters and length of 51 centimeters is 186 centimeters.
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