What is the solution to the trigonometric inequality sin(x) > cos(x) over the interval 0<= x <= 2pi radians?

Answer:
C)
Step-by-step explanation:
got it right on edge :)
The solution to the trigonometric inequality sin(x) > cos(x) over the interval 0<= x <= 2π radians will be [tex]\rm \frac{\pi}{4} < x < \frac{5 \pi}{4}[/tex].Option C is correct.
Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.
The trigonometric inequality sin(x) > cos(x) spanning the range 0 to 2 radians has the following solution:
[tex]\rm \frac{\pi}{4} < x < \frac{5 \pi}{4}[/tex]
Because when the sin(x) > cos(x) and the value is range 0 to 2 radians the value of the x must be between the 45° to 225°.The graph is attached for further clarification.
Hence option C is correct.
To learn more about inequality, refer to https://brainly.com/question/20383699
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