Answer: 34 gram of chromium produced from 50g of [tex]Cr_2O_3[/tex]
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} Cr_2O_3=\frac{50g}{152g/mol}=0.33moles[/tex]
The decomposition of [tex]Cr_2O_3[/tex] follows the equation :
[tex]2Cr_2O_3\rightarrow 4Cr+3O_2[/tex]
According to stoichiometry :
2 moles of [tex]Cr_2O_3[/tex] produce = 4 moles of [tex]Cr[/tex]
Thus 0.33 moles of [tex]Cr_2O_3[/tex] will produce=[tex]\frac{4}{2}\times 0.33=0.66moles[/tex] of [tex]Cr[/tex]
Mass of [tex]Cr=moles\times {\text {Molar mass}}=0.66moles\times 52g/mol=34g[/tex]
Thus 34 gram of chromium produced from 50g of [tex]Cr_2O_3[/tex]
