Answer:
The electron has an acceleration of 838800 [tex]\frac{m}{min^{2} }[/tex]
Explanation:
An electron has an acceleration of 2.33*10² [tex]\frac{m}{sec^{2} }[/tex]
To be able to express in units [tex]\frac{m}{min^{2} }[/tex], you must carry out the conversion taking into account that 1 [tex]\frac{m}{sec^{2} }[/tex]= 3600 [tex]\frac{m}{min^{2} }[/tex]. Then you can apply the following rule of three: if 1 [tex]\frac{m}{sec^{2} }[/tex] equals 3600 [tex]\frac{m}{min^{2} }[/tex], 2.33 * 10² [tex]\frac{m}{sec^{2} }[/tex] equals how much [tex]\frac{m}{min^{2} }[/tex]?
[tex]\frac{m}{min^{2} }=\frac{2.33*10^{2} \frac{m}{sec^{2} }*3600\frac{m}{min^{2} }}{1\frac{m}{sec^{2} }}[/tex]
[tex]\frac{m}{min^{2} }=838800[/tex]
The electron has an acceleration of 838800 [tex]\frac{m}{min^{2} }[/tex]
