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What is the molecular formula for a compound that is 34.31% sodium, 17.93% carbon, 47.76% oxygen and has a molar mass of 134.00g?

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Answer: Na2C2O4 probably sodium oxalate

Explanation: assume you have 100 g substance.

Mass of Na is m(Na) = 34.31 g, m(C) = 17.93 g and m(O) = 47.76 g.

Calculate moles n(Na) = 34.31 g/22.99 g/mol= 1.49 mol.

For C n(C) = 1.49 mol and n(O) = 2.985. You divide all by 1.49 you

Get n(Na) : n(C) : n(O) = 1:1:2 M(NaCO2) = 67 g/mol.

Divide 134:67 = 2. You get formula Na2C2O4

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