There are two isotopes of an unknown element, X-19 and X-21. The abundance of X-19 is 12.01%. Now that you have the contribution from the X-19 isotope (2.282) and from the X-21 isotope (18.48), what is the average atomic mass (in amu) of this element using four significant figures

Respuesta :

Answer: The average atomic mass of X is 16.53

Explanation:

Mass of isotope X-19  = 2.282  

% abundance of isotope X-19 = 12.01% = [tex]\frac{12.01}{100}=0.1201[/tex]

Mass of isotope X-21 = 18.48

% abundance of isotope X-21 = (100-12.01)% = [tex]\frac{100-12.01}{100}=0.8799[/tex]

Formula used for average atomic mass of an element :

[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]

[tex]A=\sum[(2.282\times 0.1201)+(18.48\times 0.8799)][/tex]

[tex]A=16.53[/tex]

Therefore, the average atomic mass of X is 16.53