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g A wheel of radius 1.2 meters initially rotates clockwise around its center with an angular speed of 10 rad/s, and it steadily increases its rate of rotation. 4 second later, the rate of rotation is 30 rad/s. What is the ratio of the angular acceleration of a point on the rim of the wheel to a point that is 0.6 meters from the center of the wheel?

Respuesta :

Answer:

 α = 5 rad / s²

Explanation:

This is a rotational kinematics exercise.

They indicate the initial velocity wo = 10 rad / s

             w = w₀ + α t

             α = [tex]\frac{w-w_o }{t}[/tex]

let's calculate

             α = [tex]\frac{30-10}{4}[/tex]

             α = 5 rad / s²

The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change

            a = α r

            v = w r

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