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A hot iron ball of mass 200 g is cooled to a temperature of 22°C from 100°C. How much heat was
lost in the process?
(Ciron = 0.444 J/g°C)
Q =mcAT

Respuesta :

Answer:

Q= -6900 J

Explanation:

use the formula Q=mC(T_2 - T_1) and sub in givens

Q=mC(T_2 - T_1)

Q= (200 g)(0.444 J/g°C)(22-100)

Q= -6900 J

The negative sign means heat is lost, which agrees with the decrease in temperature

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