Answer: 5 N
Explanation:
Given
Mass of box [tex]m=4\ kg[/tex]
acceleration of box [tex]a=2\ m/s^2[/tex]
Force applied by Manual [tex]F_m=8\ N[/tex]
Friction force [tex]f=5\ N[/tex]
The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]
Suppose [tex]F_c[/tex] is the force applied by Carlos
[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]
The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
The force is defined as the external effort applied on any object to move it or to restrict it.
Here following information is given in the question:
Mass of the box m=4 kg
The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]
The force applied by the Manual [tex]F_m=8\ N[/tex]
The frictional force is [tex]F_f=5\ N[/tex]
The net force on the body will be calculated by
[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]
The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:
[tex]F_m+F_c-F_f=F_{net}[/tex]
[tex]8+F_c-5=8[/tex]
[tex]F_c=5\ N[/tex]
Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
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