Answer:
It is a square because all the sides are equal
Step-by-step explanation:
PLEASE HELP!! SHOW ALL WORK FOR BRAINLIEST
Quadrilateral EFGH has vertices at E(10,4), F(16,4), G(16,10) and H(10,10). Based on the properties of the diagonals, is quadrilateral EFGH a rectangle, a rhombus, or a square?? Use the distance and slope formula to prove your conclusion. Must show all work, please
Using the distance formula
√(x2 - x1)² + (y2 - y1)²
When given vertices x1, y1, and x2, y2
We find the length of each side
For E(10,4), F(16,4)
√(16 - 10)² + (4 - 4)²
= √6²
= √36
= 6 units
F(16,4), G(16,10)
= √(16 - 16)² + (10 - 4)²
= √6²
= √36
= 6 units
G(16,10) and H(10,10)
= √(10 - 16)² + (10 - 10)²
= √-6²
= √36
= 6 units
E(10,4), and H(10,10)
It is a square because all the sides are equal
