Answer:
Tangential speed, V = 2.78 m/s.
Explanation:
Given the following data;
Centripetal acceleration = 28m/s²
Radius = 27.5cm to meters = 27.5/100 = 0.275 meters
To find the tangential speed;
Centripetal acceleration = V²/r
Substituting into the formula, we have;
28 = V²/0.275
V² = 28 * 0.275
V² = 7.7
Taking the square root of both sides, we have;
Tangential speed, V = 2.78 m/s.
The tangential speed of the sock will be 7.7 m/sec².Tangential speed is as the linear speed of any object travelling along a circular route.
Tangential speed is defined as the linear speed of any item travelling along a circular route.
A point on the outside edge of a turntable travels further in one complete rotation than a point towards the center.
The given data in he problem is;
a is the centripetal acceleration =28m/s?
r is the radius of 27.5cm
v is the tangential speed of the sock=?
[tex]\rm a= \frac{v^2}{r} \\\\ \rm v= \sqrt{ar} \\\\ \rm v= \sqrt{28 \times 0.275 } \\\\ \rm v=7.7 \ m/sec^2[/tex]
Hence the tangential speed of the sock will be 7.7 m/sec².
To learn more about the tangential speed refer to the link;
https://brainly.com/question/17689540
