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A hot piece of copper was dropped into 155 g of water at 23.6 °C and 2,100 J of energy was transferred to the water. What is the final temperature of the water?​

Respuesta :

dsdrajlin

Answer:

26.8 °C

Explanation:

Step 1: Given and required data

  • Mass of water (m): 155 g
  • Energy transferred to the water (Q): 2100 J
  • Initial temperature of the water (T₂): 23.6 °C
  • Final temperature of the water (T₁): ?
  • Specific heat of water (c): 4.184 J/g.°C

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C
  • The answer is When The final temperature we (reached by both copper and also water) is 38.7 °C.  This method can also be used to determine other quantities, also it helps a lot such as the specific heat of an unknown metal.

Step 1: when Given and required data is:

  • When The Mass of water (m): 155 g
  • When the Energy transferred to the water is (Q): 2100 J
  • After that initial temperature of the water is (T₂): 23.6 °C
  • Now when the Final temperature of the water is (T₁):?
  • when The Specific heat of water (c): 4.184 J/g. °C

Step 2: Now Calculate the final temperature of the water is:

  • Now We will use the following expression is:
  • Then follow this formula Q = c × m × (T₂ - T₁)

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