Answer:
the height of the building is 0.8 m.
Explanation:
Given;
mass of the object, m = 250 g = 0.25 kg
final velocity of the object, v = 4 m/s
let the height of the building = h
Apply the principle of conservation of energy to determine the height of the building;
¹/₂mv² = mgh
¹/₂v² = gh
[tex]h = \frac{v^2}{2g} \\\\h = \frac{4 ^2}{2 \times 10} \\\\h = 0.8 \ m[/tex]
Therefore, the height of the building is 0.8 m.
