A balloon rubbed against a pair of jeans gains a charge of -6x10^-6 C. If the balloon is moved to a distance of 0.25 m away from the jeans, what is the size and direction of the electric force between the balloon and jeans ?

Respuesta :

Answer: 5.184 N

Explanation:

Given

The charge on the balloon is [tex]q_1=-6\times 10^{-6}\ C[/tex]

distance between balloon and jeans is [tex]r=0.25\ m[/tex]

After rubbing jeans must acquire the same opposite charge i.e.

[tex]q_2=6\times 10^{-6}\ C[/tex]

The electrostatic force between them

[tex]\Rightarrow F=\dfrac{kq_1q_2}{r^2}\\\\\Rightarrow F=\dfrac{9\times 10^9\times 6\times 10^{-6}\times 6\times 10^{-6}}{0.25^2}\\\\ \Rightarrow F=4\times 4\times 9\times 36\times 10^{-3}=5.184\ N[/tex]

nature of force will be attractive i.e. Jeans will try to pull the balloon