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In the figure given below, AB is a diameter of the circle with center o
0
B
D
If m ZABC - 30 and m ZCAD = 140" what is m ZBAD?
600
700
80
1100
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In the figure given below AB is a diameter of the circle with center o 0 B D If m ZABC 30 and m ZCAD 140 what is m ZBAD 600 700 80 1100 Previous Type here to se class=

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Answer:

∠ BAD = 80°

Step-by-step explanation:

∠ ACB = 90° ( angle in a semicircle )

∠ CAB = 180° - (90 + 30)° ← sum of angles in Δ ABC

∠ CAB = 180° - 120° = 60°

Then

∠ BAD = ∠ CAD - ∠ CAB = 140° - 60° = 80°

Answer:

80° is the answer

Step-by-step explanation:

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