Answer:
The area of the pyramid is 703.97 ft²
Step-by-step explanation:
The lateral area of a right square pyramid is given as;
[tex]A_l =a \sqrt{a^2 + 4h^2}[/tex]
where;
a is base length
h is the vertical height of the pyramid
The vertical height of the pyramid is calculated as follows;
the vertical height passes through the center of the base.
half of the base = 8 ft
the slant height = hypotenuse side of the right triangle = 22 ft
Thus; h² = 22² - 8²
h² = 420
h = √420
h = 20.493 ft
The area of the pyramid is calculated as;
[tex]A_l =a \sqrt{a^2 + 4h^2}\\\\A_l =16\sqrt{16^2 + 4(20.493)^2} \\\\A_l = 703.97 \ ft^2[/tex]
Therefore, the area of the pyramid is 703.97 ft²
