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A steel spring had a spring constant of 2 x 10^2 Nm^-1. Calculate the weight of an object which when attached to the unloaded spring produces an extension of 50mm. The elastic limit is not exceeded

Respuesta :

menushaeshan

Answer:

10 N

Explanation:

50 mm in m is 50 x 10^-3 m

Therefore : By using f=kx

200x 0.05 = f = 10 N

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