Respuesta :

q = mCpΔT

Cp = 2.22 J/g°C
m = 150 g
ΔT = T(final) - T(initial) = -15°C - (-30°C) = +15°C

q = (150 g)(2.22 J/g°C)(15°C) = 4,995 J

Answer:

5.00 kj

Explanation:

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