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Circumference = 21 + 2.5 π
Or, 2×π×r = 21 + 2.5 π
[tex]or, \: \pi \times r = \frac{21 + 2.5 π}{2} [/tex]
[tex]or, \: \pi \times r = \frac{21}{2} + \frac{25\pi}{2} [/tex]
[tex]or, \: r \: = ( \frac{21}{2} + \frac{25\pi}{2} ) \div \frac{22}{7} [/tex]
[tex]or, \: r = (\frac{7}{22} \times \frac{21}{2} ) + ( \frac{7}{22} \times \frac{2.5\pi}{2} )[/tex]
[tex]or, \: r = (\frac{7}{22} \times \frac{21}{2} ) + ( \frac{7}{22} \times \frac{2.5}{2} \times \frac{22}{7} )[/tex]
[tex]or, \: r = (\frac{7}{22} \times \frac{21}{2} ) + ( \frac{2.5}{2} )[/tex]
[tex]or, \: r = ( \frac{147}{44} ) + ( \frac{55}{44} )[/tex]
[tex]or, \: r = ( \frac{101}{22} )[/tex]
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Now, area of the circle
= π r²
[tex] = \frac{22}{7} \times \ { \frac{101}{22} }^{2} [/tex]
[tex] = \frac{22}{7} \times \ { \frac{101}{22} } \times \frac{101}{22} [/tex]
[tex] = { \frac{101}{7} } \times \frac{101}{22} [/tex]
[tex] = \frac{10201}{154} [/tex]
[tex] = 66.24[/tex]
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