Respuesta :
Answer:
0.06 or 6%
Step-by-step explanation:
Continuous Compounding:
[tex]A=Pe^{rt}\\1220=610e^{12r}\\\\r=\frac{ln(2)}{12} \\\\r=0.058[/tex]
0.06 or 6%
Answer:
0.06 or 6%
Step-by-step explanation:
Continuous Compounding:
[tex]A=Pe^{rt}\\1220=610e^{12r}\\\\r=\frac{ln(2)}{12} \\\\r=0.058[/tex]
0.06 or 6%