Respuesta :

dsdrajlin

Answer:

147 J

Explanation:

Step 1: Given and required data

  • Mass of zinc (m): 6.41 g
  • Specific heat capacity of zinc (c): 0.377 J/g.°C
  • Initial temperature (T₁): 98.1 °C
  • Final temperature (T₂): 37.4 °C

Step 2: Calculate the amount of heat (Q) lost by the piece of zinc

We will use the following expression.

Q = c × m × (T₂ - T₁)

Q = (0.377 J/g.°C) × 6.41 g × (37.4 °C - 98.1 °C) = -147 J

The piece of zinc will lose 147 J in the form of heat.

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