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A swimmer can inhale exactly 0.25 moles of air before diving underwater. What will be the total volume of the swimmer’s lungs at 0.97 atm and 17.6 0C?

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Answer:

6.14 L

Explanation:

To answer this question we'll use the PV=nRT formula, where:

  • P = 0.97 atm
  • V = ?
  • n = 0.25 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 17.6 °C ⇒ 17.6 + 273.16 = 209.76 K

We input the data:

  • 0.97 atm * V = 0.25 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 209.76 K

And solve for V:

  • V = 6.14 L

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