Answer:
That would be 90 grams
Explanation:
This should be right but please, please, please correct me if I'm worng because I dont want anyone to fail because of me. Have a great day luv <3
The answer is option B , 90 grams of potassium chloride(KCl) is needed to saturate exactly 300 grams of water at 10°C
The measure of the degree to which a substance gets dissolved in a solvent to become a solution.
The solubility of KCl in water at 10°C is 31.2gm/100gm of water .
So in 300 gm of water 3 * 31.2 gm = 93.6 gm
Using Significant Figures we can select option B i.e. 90 gm.
Hence Option B , 90 grams of potassium chloride is needed to saturate exactly 300 grams of water at 10°C
To know more about Solubilty
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